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For lim⁡x→2(3x+1)=7\lim_{x\to 2}(3x + 1) = 7, find the largest δ>0\delta > 0 such that ∣(3x+1)−7∣<0.03|(3x+1) - 7| < 0.03 whenever 0<∣x−2∣<δ0 < |x - 2| < \delta.
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