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In successive cancellation, L+=L2+(1)u^1L1L^{+} = L_2 + (-1)^{\hat u_1} L_1. With L1=0.4L_1 = 0.4, L2=3.0L_2 = 3.0 and u^1=1\hat u_1 = 1, compute L+L^{+}.
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