1 / 15
Let A=PDP−1A=PDP^{-1} with D=(100−2)D=\begin{pmatrix}1&0\\0&-2\end{pmatrix}. Find the (2,2)(2,2) entry of D5D^{5}, which is also the second diagonal entry in A5=PD5P−1A^{5}=PD^{5}P^{-1}.
Review the explanation for this topic →

Your answer