Generalized Eigenvectors and Jordan Form

Minimal polynomials, the Cayley-Hamilton theorem, generalized eigenvectors, Jordan normal form, and the matrix exponential.0/11 mastered

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For

A=\begin{pmatrix}1&2\\3&4\end{pmatrix}

p(\lambda)=\lambda^{2}-5\lambda-2

. Cayley-Hamilton gives

A^{2}=\alpha A+\beta I

. Find

\alpha

Your answer

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